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numpy where condition output explained

Ask Time:2018-04-20T07:15:10         Author:user1050619

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Im trying to understand numpy where condition.

>>> import numpy as np
>>> x = np.arange(9.).reshape(3, 3)
>>> x
array([[ 0.,  1.,  2.],
       [ 3.,  4.,  5.],
       [ 6.,  7.,  8.]])
>>> np.where( x > 5 )
(array([2, 2, 2]), array([0, 1, 2]))

IN the above case, what does the output actually mean, array([0,1,2]) I actually see in the input what is array([2,2,2])

Author:user1050619,eproduced under the CC 4.0 BY-SA copyright license with a link to the original source and this disclaimer.
Link to original article:https://stackoverflow.com/questions/49931594/numpy-where-condition-output-explained
Md Johirul Islam :

Th first array indicates the row number and the second array indicates the corresponding column number.\n\nIf the array is following:\n\narray([[ 0., 1., 2.],\n [ 3., 4., 5.],\n [ 6., 7., 8.]])\n\n\nThen the following\n\n(array([2, 2, 2]), array([0, 1, 2]))\n\n\nCan be interpreted as\n\narray(2,0) => 6\narray(2,1) => 7\narray (2,2) => 8\n",
2018-04-19T23:20:20
NaN :

You might also want to know where those values appear visually in your array. In such cases, you can return the array's value where the condition is True and a null value where they are false. In the example below, the value of x is returned at the position where x>5, otherwise assign -1.\n\nx = np.arange(9.).reshape(3, 3)\nnp.where(x>5, x, -1)\narray([[-1., -1., -1.],\n [-1., -1., -1.],\n [ 6., 7., 8.]])\n",
2018-04-20T04:58:49
yy