I'm pretty new to Docker, and completely baffled as to why my container exits upon start.
I've built an Ubuntu image of which starts Apache and fail2ban upon boot. I'm unsure as to whether it's an issue with the Dockerfile, or the command I am running to start the container.
I've tried:
docker run -d -p 127.0.0.1:80:80 image
docker run -d -ti -p 127.0.0.1:80:80 image
docker run -d -ti -p 127.0.0.1:80:80 image /bin/bash
The Dockerfile is as follows:
FROM ubuntu:latest
RUN \
apt-get update && \
apt-get -y upgrade && \
apt-get install -y build-essential && \
apt-get install -y iptables && \
apt-get install -y software-properties-common && \
apt-get install -y apache2 fail2ban && \
rm -rf /etc/fail2ban/jail.conf
ADD index.html /var/www/html/
ADD jail.conf /etc/fail2ban/
ENV HOME /root
WORKDIR /root
EXPOSE 80 443
ENTRYPOINT service apache2 start && service fail2ban start
CMD ["bash"]
I can jump into the container itself with:
docker exec -it image /bin/bash
But the moment I try to run it whilst staying within the host, it fails. Help?
vladmihaisima :
Considering your question, where you mention \"upon boot\" I think it would be useful to read https://docs.docker.com/config/containers/multi-service_container/.\n\nIn a nutshell docker containers do not \"boot\" as a normal system, they start a process and execute it until it exits. \n\nSo, if you want to start two processes you can do a wrapper script as explained at the link above.",
2019-04-04T14:04:27