Iamblichus :
\nYou can use localeCompare:\n\n\na.localeCompare(b)\n\n\nThis will return 1 or -1 depending on which string is lexicographically greater.\n\n\nDirectly comparing both strings would also work:\n\n\na > b\n\n\nThis will return true or false.\n\nReference:\n\n\nString.prototype.localeCompare()\n",
2020-02-11T11:59:42